25x^2+20xu+4u^2=0

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Solution for 25x^2+20xu+4u^2=0 equation: 


Simplifying
25x2 + 20xu + 4u2 = 0

Reorder the terms:
20ux + 4u2 + 25x2 = 0

Solving
20ux + 4u2 + 25x2 = 0

Solving for variable 'u'.

Factor a trinomial.
(2u + 5x)(2u + 5x) = 0


Subproblem 1
Set the factor '(2u + 5x)' equal to zero and attempt to solve:

Simplifying
2u + 5x = 0

Solving
2u + 5x = 0

Move all terms containing u to the left, all other terms to the right.

Add '-5x' to each side of the equation.
2u + 5x + -5x = 0 + -5x

Combine like terms: 5x + -5x = 0
2u + 0 = 0 + -5x
2u = 0 + -5x
Remove the zero:
2u = -5x

Divide each side by '2'.
u = -2.5x

Simplifying
u = -2.5x

Subproblem 2
Set the factor '(2u + 5x)' equal to zero and attempt to solve:

Simplifying
2u + 5x = 0

Solving
2u + 5x = 0

Move all terms containing u to the left, all other terms to the right.

Add '-5x' to each side of the equation.
2u + 5x + -5x = 0 + -5x

Combine like terms: 5x + -5x = 0
2u + 0 = 0 + -5x
2u = 0 + -5x
Remove the zero:
2u = -5x

Divide each side by '2'.
u = -2.5x

Simplifying
u = -2.5x
Solution
u = {-2.5x, -2.5x}

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